Base | Representation |
---|---|
bin | 11111010111000111011… |
… | …011001110110111001111 |
3 | 21122000202022210212121201 |
4 | 133113013123032313033 |
5 | 240302143322420142 |
6 | 4330014523410331 |
7 | 311462664214324 |
oct | 37270733166717 |
9 | 7560668725551 |
10 | 2155124420047 |
11 | 760a8a607625 |
12 | 2a98169839a7 |
13 | 1282c5686131 |
14 | 76446a4cb4b |
15 | 3b0d68ddab7 |
hex | 1f5c76cedcf |
2155124420047 has 2 divisors, whose sum is σ = 2155124420048. Its totient is φ = 2155124420046.
The previous prime is 2155124420023. The next prime is 2155124420131. The reversal of 2155124420047 is 7400244215512.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2155124420047 is a prime.
It is a super-2 number, since 2×21551244200472 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2155124419988 and 2155124420015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2155124420447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1077562210023 + 1077562210024.
It is an arithmetic number, because the mean of its divisors is an integer number (1077562210024).
Almost surely, 22155124420047 is an apocalyptic number.
2155124420047 is a deficient number, since it is larger than the sum of its proper divisors (1).
2155124420047 is an equidigital number, since it uses as much as digits as its factorization.
2155124420047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 89600, while the sum is 37.
Adding to 2155124420047 its reverse (7400244215512), we get a palindrome (9555368635559).
The spelling of 2155124420047 in words is "two trillion, one hundred fifty-five billion, one hundred twenty-four million, four hundred twenty thousand, forty-seven".
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