Base | Representation |
---|---|
bin | 11111010111000111011… |
… | …011001110110110110111 |
3 | 21122000202022210212120211 |
4 | 133113013123032312313 |
5 | 240302143322420043 |
6 | 4330014523410251 |
7 | 311462664214261 |
oct | 37270733166667 |
9 | 7560668725524 |
10 | 2155124420023 |
11 | 760a8a607603 |
12 | 2a9816983987 |
13 | 1282c5686113 |
14 | 76446a4cb31 |
15 | 3b0d68dda9d |
hex | 1f5c76cedb7 |
2155124420023 has 2 divisors, whose sum is σ = 2155124420024. Its totient is φ = 2155124420022.
The previous prime is 2155124420021. The next prime is 2155124420047. The reversal of 2155124420023 is 3200244215512.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2155124420023 - 21 = 2155124420021 is a prime.
It is a super-2 number, since 2×21551244200232 (a number of 25 digits) contains 22 as substring.
Together with 2155124420021, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2155124420021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1077562210011 + 1077562210012.
It is an arithmetic number, because the mean of its divisors is an integer number (1077562210012).
Almost surely, 22155124420023 is an apocalyptic number.
2155124420023 is a deficient number, since it is larger than the sum of its proper divisors (1).
2155124420023 is an equidigital number, since it uses as much as digits as its factorization.
2155124420023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 2155124420023 its reverse (3200244215512), we get a palindrome (5355368635535).
The spelling of 2155124420023 in words is "two trillion, one hundred fifty-five billion, one hundred twenty-four million, four hundred twenty thousand, twenty-three".
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