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2155200103 = 7307885729
BaseRepresentation
bin1000000001110101…
…1011111001100111
312120012101111202001
42000131123321213
513403212400403
6553505230131
7104256620140
oct20035337147
95505344661
102155200103
11a06610811
12501932347
13284677144
14166338ac7
15c931cc1d
hex8075be67

2155200103 has 4 divisors (see below), whose sum is σ = 2463085840. Its totient is φ = 1847314368.

The previous prime is 2155200083. The next prime is 2155200107. The reversal of 2155200103 is 3010025512.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2155200103 - 29 = 2155199591 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2155200107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 153942858 + ... + 153942871.

It is an arithmetic number, because the mean of its divisors is an integer number (615771460).

Almost surely, 22155200103 is an apocalyptic number.

2155200103 is a deficient number, since it is larger than the sum of its proper divisors (307885737).

2155200103 is an equidigital number, since it uses as much as digits as its factorization.

2155200103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 307885736.

The product of its (nonzero) digits is 300, while the sum is 19.

The square root of 2155200103 is about 46424.1327651901. The cubic root of 2155200103 is about 1291.7025979118.

Adding to 2155200103 its reverse (3010025512), we get a palindrome (5165225615).

The spelling of 2155200103 in words is "two billion, one hundred fifty-five million, two hundred thousand, one hundred three".

Divisors: 1 7 307885729 2155200103