Base | Representation |
---|---|
bin | 11111010111011001111… |
… | …001011010001000111111 |
3 | 21122001112220221110001022 |
4 | 133113121321122020333 |
5 | 240303312141223242 |
6 | 4330105353534355 |
7 | 311503446300122 |
oct | 37273171321077 |
9 | 7561486843038 |
10 | 2155434320447 |
11 | 761129533361 |
12 | 2a98a27143bb |
13 | 12834493c355 |
14 | 76475c7c3b9 |
15 | 3b103c060d2 |
hex | 1f5d9e5a23f |
2155434320447 has 2 divisors, whose sum is σ = 2155434320448. Its totient is φ = 2155434320446.
The previous prime is 2155434320443. The next prime is 2155434320453. The reversal of 2155434320447 is 7440234345512.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2155434320447 - 22 = 2155434320443 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2155434320398 and 2155434320407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2155434320443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1077717160223 + 1077717160224.
It is an arithmetic number, because the mean of its divisors is an integer number (1077717160224).
Almost surely, 22155434320447 is an apocalyptic number.
2155434320447 is a deficient number, since it is larger than the sum of its proper divisors (1).
2155434320447 is an equidigital number, since it uses as much as digits as its factorization.
2155434320447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1612800, while the sum is 44.
Adding to 2155434320447 its reverse (7440234345512), we get a palindrome (9595668665959).
The spelling of 2155434320447 in words is "two trillion, one hundred fifty-five billion, four hundred thirty-four million, three hundred twenty thousand, four hundred forty-seven".
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