Base | Representation |
---|---|
bin | 1000000001111010… |
… | …1110101111010101 |
3 | 12120020000202012002 |
4 | 2000132232233111 |
5 | 13403304230123 |
6 | 553520405045 |
7 | 104262532316 |
oct | 20036565725 |
9 | 5506022162 |
10 | 2155539413 |
11 | a06822735 |
12 | 501a76785 |
13 | 284765711 |
14 | 1663c660d |
15 | c9388528 |
hex | 807aebd5 |
2155539413 has 4 divisors (see below), whose sum is σ = 2157294540. Its totient is φ = 2153784288.
The previous prime is 2155539409. The next prime is 2155539431. The reversal of 2155539413 is 3149355512.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1373665969 + 781873444 = 37063^2 + 27962^2 .
It is a cyclic number.
It is not a de Polignac number, because 2155539413 - 22 = 2155539409 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2155539473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 875720 + ... + 878177.
It is an arithmetic number, because the mean of its divisors is an integer number (539323635).
Almost surely, 22155539413 is an apocalyptic number.
It is an amenable number.
2155539413 is a deficient number, since it is larger than the sum of its proper divisors (1755127).
2155539413 is a wasteful number, since it uses less digits than its factorization.
2155539413 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1755126.
The product of its digits is 81000, while the sum is 38.
The square root of 2155539413 is about 46427.7870784297. The cubic root of 2155539413 is about 1291.7703819672.
The spelling of 2155539413 in words is "two billion, one hundred fifty-five million, five hundred thirty-nine thousand, four hundred thirteen".
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