2164512703 has 4 divisors (see below), whose sum is σ = 2164614120. Its totient is φ = 2164411288.

The previous prime is 2164512683. The next prime is 2164512751. The reversal of 2164512703 is 3072154612.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 2164512703 - 2⁹ = 2164512191 is a prime.

It is a super-3 number, since 3×2164512703³ (a number of 29 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2164512793) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4900 + ... + 65977.

It is an arithmetic number, because the mean of its divisors is an integer number (541153530).

Almost surely, 2^2164512703 is an apocalyptic number.

2164512703 is a deficient number, since it is larger than the sum of its proper divisors (101417).

2164512703 is an equidigital number, since it uses as much as digits as its factorization.

2164512703 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 101416.

The product of its (nonzero) digits is 10080, while the sum is 31.

The square root of 2164512703 is about 46524.3237779981. The cubic root of 2164512703 is about 1293.5604030065.

The spelling of 2164512703 in words is "two billion, one hundred sixty-four million, five hundred twelve thousand, seven hundred three".