Base | Representation |
---|---|
bin | 1100100111101010111… |
… | …0101011000011100011 |
3 | 202201121200102002111022 |
4 | 3021322232223003203 |
5 | 12023010144421011 |
6 | 243333331240055 |
7 | 21443455443611 |
oct | 3117256530343 |
9 | 681550362438 |
10 | 216807420131 |
11 | 83a47155765 |
12 | 3602844902b |
13 | 175a24557a3 |
14 | a6ca3906b1 |
15 | 598dcaa8db |
hex | 327abab0e3 |
216807420131 has 6 divisors (see below), whose sum is σ = 228818911932. Its totient is φ = 205396502940.
The previous prime is 216807420073. The next prime is 216807420163. The reversal of 216807420131 is 131024708612.
It is a de Polignac number, because none of the positive numbers 2k-216807420131 is a prime.
It is a super-2 number, since 2×2168074201312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 216807420091 and 216807420100.
It is not an unprimeable number, because it can be changed into a prime (216807420191) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 300286925 + ... + 300287646.
It is an arithmetic number, because the mean of its divisors is an integer number (38136485322).
Almost surely, 2216807420131 is an apocalyptic number.
216807420131 is a deficient number, since it is larger than the sum of its proper divisors (12011491801).
216807420131 is an equidigital number, since it uses as much as digits as its factorization.
216807420131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 600574609 (or 600574590 counting only the distinct ones).
The product of its (nonzero) digits is 16128, while the sum is 35.
The spelling of 216807420131 in words is "two hundred sixteen billion, eight hundred seven million, four hundred twenty thousand, one hundred thirty-one".
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