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2172416223347 is a prime number
BaseRepresentation
bin11111100111001110000…
…110001110100001110011
321200200101102101111101222
4133213032012032201303
5241043102023121342
64341554431015255
7312644333136116
oct37471606164163
97620342344358
102172416223347
11768353361357
122b104196a52b
13129b1cc674c6
14772073aa57d
153b799a05ed2
hex1f9ce18e873

2172416223347 has 2 divisors, whose sum is σ = 2172416223348. Its totient is φ = 2172416223346.

The previous prime is 2172416223277. The next prime is 2172416223349. The reversal of 2172416223347 is 7433226142712.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2172416223347 - 28 = 2172416223091 is a prime.

It is a super-2 number, since 2×21724162233472 (a number of 25 digits) contains 22 as substring.

Together with 2172416223349, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2172416223298 and 2172416223307.

It is not a weakly prime, because it can be changed into another prime (2172416223349) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1086208111673 + 1086208111674.

It is an arithmetic number, because the mean of its divisors is an integer number (1086208111674).

Almost surely, 22172416223347 is an apocalyptic number.

2172416223347 is a deficient number, since it is larger than the sum of its proper divisors (1).

2172416223347 is an equidigital number, since it uses as much as digits as its factorization.

2172416223347 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 677376, while the sum is 44.

The spelling of 2172416223347 in words is "two trillion, one hundred seventy-two billion, four hundred sixteen million, two hundred twenty-three thousand, three hundred forty-seven".