Base | Representation |
---|---|
bin | 1100101010000000010… |
… | …0110011111100000111 |
3 | 202210020100101122222112 |
4 | 3022200010303330013 |
5 | 12030301044340204 |
6 | 243515432451235 |
7 | 21465134225006 |
oct | 3124004637407 |
9 | 683210348875 |
10 | 217433980679 |
11 | 842388a49a3 |
12 | 36182249b1b |
13 | 176721c0986 |
14 | a74968cc3d |
15 | 59c8cc326e |
hex | 32a0133f07 |
217433980679 has 2 divisors, whose sum is σ = 217433980680. Its totient is φ = 217433980678.
The previous prime is 217433980637. The next prime is 217433980733. The reversal of 217433980679 is 976089334712.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 217433980679 - 220 = 217432932103 is a prime.
It is a super-4 number, since 4×2174339806794 (a number of 46 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (217433920679) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 108716990339 + 108716990340.
It is an arithmetic number, because the mean of its divisors is an integer number (108716990340).
Almost surely, 2217433980679 is an apocalyptic number.
217433980679 is a deficient number, since it is larger than the sum of its proper divisors (1).
217433980679 is an equidigital number, since it uses as much as digits as its factorization.
217433980679 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13716864, while the sum is 59.
The spelling of 217433980679 in words is "two hundred seventeen billion, four hundred thirty-three million, nine hundred eighty thousand, six hundred seventy-nine".
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