Base | Representation |
---|---|
bin | 100000000000111010111… |
… | …000110010010000111111 |
3 | 21210022121120020120110012 |
4 | 200000322320302100333 |
5 | 242021110333020111 |
6 | 4402400551333435 |
7 | 314642220552362 |
oct | 40007270622077 |
9 | 7708546216405 |
10 | 2200011220031 |
11 | 779023a85839 |
12 | 2b646338127b |
13 | 12c5c9cb1501 |
14 | 786a42520d9 |
15 | 3c36241b48b |
hex | 2003ae3243f |
2200011220031 has 2 divisors, whose sum is σ = 2200011220032. Its totient is φ = 2200011220030.
The previous prime is 2200011220021. The next prime is 2200011220093. The reversal of 2200011220031 is 1300221100022.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2200011220031 - 214 = 2200011203647 is a prime.
It is a super-2 number, since 2×22000112200312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2200011219988 and 2200011220015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2200011220021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1100005610015 + 1100005610016.
It is an arithmetic number, because the mean of its divisors is an integer number (1100005610016).
Almost surely, 22200011220031 is an apocalyptic number.
2200011220031 is a deficient number, since it is larger than the sum of its proper divisors (1).
2200011220031 is an equidigital number, since it uses as much as digits as its factorization.
2200011220031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 14.
Adding to 2200011220031 its reverse (1300221100022), we get a palindrome (3500232320053).
The spelling of 2200011220031 in words is "two trillion, two hundred billion, eleven million, two hundred twenty thousand, thirty-one".
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