Base | Representation |
---|---|
bin | 100000000001000000110… |
… | …110010000100110000111 |
3 | 21210022212112102011011111 |
4 | 200001000312100212013 |
5 | 242021311433034002 |
6 | 4402414522545451 |
7 | 314644543550641 |
oct | 40010066204607 |
9 | 7708775364144 |
10 | 2200111221127 |
11 | 779075478076 |
12 | 2b6490968287 |
13 | 12c614925661 |
14 | 786b3643891 |
15 | 3c36b0c13d7 |
hex | 20040d90987 |
2200111221127 has 2 divisors, whose sum is σ = 2200111221128. Its totient is φ = 2200111221126.
The previous prime is 2200111221083. The next prime is 2200111221131. The reversal of 2200111221127 is 7211221110022.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2200111221127 - 223 = 2200102832519 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2200111221098 and 2200111221107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2200111221137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1100055610563 + 1100055610564.
It is an arithmetic number, because the mean of its divisors is an integer number (1100055610564).
Almost surely, 22200111221127 is an apocalyptic number.
2200111221127 is a deficient number, since it is larger than the sum of its proper divisors (1).
2200111221127 is an equidigital number, since it uses as much as digits as its factorization.
2200111221127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 22.
Adding to 2200111221127 its reverse (7211221110022), we get a palindrome (9411332331149).
The spelling of 2200111221127 in words is "two trillion, two hundred billion, one hundred eleven million, two hundred twenty-one thousand, one hundred twenty-seven".
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