Base | Representation |
---|---|
bin | 10100011111010111… |
… | …101010001001010001 |
3 | 2002210022000022102221 |
4 | 110133113222021101 |
5 | 330024242211423 |
6 | 14035052341041 |
7 | 1406131352212 |
oct | 243727521121 |
9 | 62708008387 |
10 | 22001132113 |
11 | 937007a214 |
12 | 4320174781 |
13 | 20c815a38c |
14 | 10c9d97409 |
15 | 88b7a3e5d |
hex | 51f5ea251 |
22001132113 has 2 divisors, whose sum is σ = 22001132114. Its totient is φ = 22001132112.
The previous prime is 22001132089. The next prime is 22001132129. The reversal of 22001132113 is 31123110022.
It is an a-pointer prime, because the next prime (22001132129) can be obtained adding 22001132113 to its sum of digits (16).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12542208064 + 9458924049 = 111992^2 + 97257^2 .
It is a cyclic number.
It is not a de Polignac number, because 22001132113 - 221 = 21999034961 is a prime.
It is not a weakly prime, because it can be changed into another prime (22001132183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11000566056 + 11000566057.
It is an arithmetic number, because the mean of its divisors is an integer number (11000566057).
Almost surely, 222001132113 is an apocalyptic number.
It is an amenable number.
22001132113 is a deficient number, since it is larger than the sum of its proper divisors (1).
22001132113 is an equidigital number, since it uses as much as digits as its factorization.
22001132113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 22001132113 its reverse (31123110022), we get a palindrome (53124242135).
The spelling of 22001132113 in words is "twenty-two billion, one million, one hundred thirty-two thousand, one hundred thirteen".
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