Base | Representation |
---|---|
bin | 1000011001001000110011 |
3 | 11010202222202 |
4 | 20121020303 |
5 | 1030400430 |
6 | 115053415 |
7 | 24462221 |
oct | 10311063 |
9 | 4122882 |
10 | 2200115 |
11 | 1272a85 |
12 | 8a126b |
13 | 5c0558 |
14 | 413b11 |
15 | 2d6d45 |
hex | 219233 |
2200115 has 4 divisors (see below), whose sum is σ = 2640144. Its totient is φ = 1760088.
The previous prime is 2200103. The next prime is 2200139. The reversal of 2200115 is 5110022.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 5110022 = 2 ⋅2555011.
It is a cyclic number.
It is not a de Polignac number, because 2200115 - 28 = 2199859 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2200096 and 2200105.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220007 + ... + 220016.
It is an arithmetic number, because the mean of its divisors is an integer number (660036).
22200115 is an apocalyptic number.
2200115 is a deficient number, since it is larger than the sum of its proper divisors (440029).
2200115 is an equidigital number, since it uses as much as digits as its factorization.
2200115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 440028.
The product of its (nonzero) digits is 20, while the sum is 11.
The square root of 2200115 is about 1483.2784634046. The cubic root of 2200115 is about 130.0614108277.
Adding to 2200115 its reverse (5110022), we get a palindrome (7310137).
The spelling of 2200115 in words is "two million, two hundred thousand, one hundred fifteen".
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