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2201210122013 = 7314458588859
BaseRepresentation
bin100000000010000010010…
…110001110111100011101
321210102201010012002210022
4200002002112032330131
5242031034242401023
64403115540121525
7315014016215420
oct40020226167435
97712633162708
102201210122013
11779589801621
122b67389962a5
1312c75b4acc76
14787795779b7
153c3d27db7c8
hex2008258ef1d

2201210122013 has 4 divisors (see below), whose sum is σ = 2515668710880. Its totient is φ = 1886751533148.

The previous prime is 2201210121997. The next prime is 2201210122021. The reversal of 2201210122013 is 3102210121022.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2201210122013 - 24 = 2201210121997 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2201210121982 and 2201210122000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2201210121013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 157229294423 + ... + 157229294436.

It is an arithmetic number, because the mean of its divisors is an integer number (628917177720).

Almost surely, 22201210122013 is an apocalyptic number.

It is an amenable number.

2201210122013 is a deficient number, since it is larger than the sum of its proper divisors (314458588867).

2201210122013 is an equidigital number, since it uses as much as digits as its factorization.

2201210122013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 314458588866.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 2201210122013 its reverse (3102210121022), we get a palindrome (5303420243035).

Subtracting 2201210122013 from its reverse (3102210121022), we obtain a palindrome (900999999009).

The spelling of 2201210122013 in words is "two trillion, two hundred one billion, two hundred ten million, one hundred twenty-two thousand, thirteen".

Divisors: 1 7 314458588859 2201210122013