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22013104013 is a prime number
BaseRepresentation
bin10100100000000101…
…010100111110001101
32002211010112112210122
4110200011110332031
5330040323312023
614040201114325
71406335203545
oct244005247615
962733475718
1022013104013
11937690694a
1243241889a5
1320ca78c644
1410cb7d2325
1588c86b2c8
hex520154f8d

22013104013 has 2 divisors, whose sum is σ = 22013104014. Its totient is φ = 22013104012.

The previous prime is 22013103991. The next prime is 22013104019. The reversal of 22013104013 is 31040131022.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13218790729 + 8794313284 = 114973^2 + 93778^2 .

It is a cyclic number.

It is not a de Polignac number, because 22013104013 - 26 = 22013103949 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 22013103982 and 22013104000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (22013104019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11006552006 + 11006552007.

It is an arithmetic number, because the mean of its divisors is an integer number (11006552007).

Almost surely, 222013104013 is an apocalyptic number.

It is an amenable number.

22013104013 is a deficient number, since it is larger than the sum of its proper divisors (1).

22013104013 is an equidigital number, since it uses as much as digits as its factorization.

22013104013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 22013104013 its reverse (31040131022), we get a palindrome (53053235035).

The spelling of 22013104013 in words is "twenty-two billion, thirteen million, one hundred four thousand, thirteen".