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2201311140 = 22357231811259
BaseRepresentation
bin1000001100110101…
…0101011110100100
312200102011012012020
42003031111132210
514002013424030
61002233423140
7105356556510
oct20315253644
95612135166
102201311140
11a2a645706
1251526aab0
132910a0392
1416c4dd140
15cd3ca510
hex833557a4

2201311140 has 192 divisors, whose sum is σ = 7396945920. Its totient is φ = 478241280.

The previous prime is 2201311127. The next prime is 2201311153. The reversal of 2201311140 is 411131022.

It is an interprime number because it is at equal distance from previous prime (2201311127) and next prime (2201311153).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1747831 + ... + 1749089.

It is an arithmetic number, because the mean of its divisors is an integer number (38525760).

Almost surely, 22201311140 is an apocalyptic number.

2201311140 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2201311140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3698472960).

2201311140 is an abundant number, since it is smaller than the sum of its proper divisors (5195634780).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2201311140 is a wasteful number, since it uses less digits than its factorization.

2201311140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1482 (or 1480 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 2201311140 is about 46918.1323157689. The cubic root of 2201311140 is about 1300.8497678846.

Adding to 2201311140 its reverse (411131022), we get a palindrome (2612442162).

It can be divided in two parts, 22013 and 11140, that added together give a triangular number (33153 = T257).

The spelling of 2201311140 in words is "two billion, two hundred one million, three hundred eleven thousand, one hundred forty".