220211112113 has 2 divisors, whose sum is σ = 220211112114. Its totient is φ = 220211112112.

The previous prime is 220211112083. The next prime is 220211112131. The reversal of 220211112113 is 311211112022.

It is a happy number.

220211112113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (220211112131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 166784025664 + 53427086449 = 408392^2 + 231143^2 .

It is a cyclic number.

It is not a de Polignac number, because 220211112113 - 2¹⁴ = 220211095729 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 220211112091 and 220211112100.

It is not a weakly prime, because it can be changed into another prime (220211112613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110105556056 + 110105556057.

It is an arithmetic number, because the mean of its divisors is an integer number (110105556057).

Almost surely, 2^220211112113 is an apocalyptic number.

It is an amenable number.

220211112113 is a deficient number, since it is larger than the sum of its proper divisors (1).

220211112113 is an equidigital number, since it uses as much as digits as its factorization.

220211112113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 220211112113 its reverse (311211112022), we get a palindrome (531422224135).

Subtracting 220211112113 from its reverse (311211112022), we obtain a palindrome (90999999909).

The spelling of 220211112113 in words is "two hundred twenty billion, two hundred eleven million, one hundred twelve thousand, one hundred thirteen".