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2211021000143 is a prime number
BaseRepresentation
bin100000001011001011000…
…111110000110111001111
321211101000212002100110222
4200023023013300313033
5242211132334001033
64411421245221555
7315512106260564
oct40131307606717
97741025070428
102211021000143
1178276379356a
122b86165618bb
13130662c515b7
147902a54a86b
153c7a8c8d598
hex202cb1f0dcf

2211021000143 has 2 divisors, whose sum is σ = 2211021000144. Its totient is φ = 2211021000142.

The previous prime is 2211021000091. The next prime is 2211021000179. The reversal of 2211021000143 is 3410001201122.

2211021000143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2211021000143 - 218 = 2211020737999 is a prime.

It is a super-2 number, since 2×22110210001432 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2211021008143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1105510500071 + 1105510500072.

It is an arithmetic number, because the mean of its divisors is an integer number (1105510500072).

Almost surely, 22211021000143 is an apocalyptic number.

2211021000143 is a deficient number, since it is larger than the sum of its proper divisors (1).

2211021000143 is an equidigital number, since it uses as much as digits as its factorization.

2211021000143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 2211021000143 its reverse (3410001201122), we get a palindrome (5621022201265).

The spelling of 2211021000143 in words is "two trillion, two hundred eleven billion, twenty-one million, one hundred forty-three", and thus it is an aban number.