Base | Representation |
---|---|
bin | 1010000011011111011110… |
… | …10101101001000000100011 |
3 | 2220021201022200211010200022 |
4 | 11001233233111221000203 |
5 | 10344223203244201011 |
6 | 115005142522544055 |
7 | 4441260444642101 |
oct | 501575725510043 |
9 | 86251280733608 |
10 | 22110212100131 |
11 | 70549853559a1 |
12 | 259113536802b |
13 | c44ca3c77a2c |
14 | 5661d6142c71 |
15 | 28520d8a58db |
hex | 141bef569023 |
22110212100131 has 2 divisors, whose sum is σ = 22110212100132. Its totient is φ = 22110212100130.
The previous prime is 22110212100043. The next prime is 22110212100161. The reversal of 22110212100131 is 13100121201122.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-22110212100131 is a prime.
It is a super-2 number, since 2×221102121001312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (22110212100161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11055106050065 + 11055106050066.
It is an arithmetic number, because the mean of its divisors is an integer number (11055106050066).
Almost surely, 222110212100131 is an apocalyptic number.
22110212100131 is a deficient number, since it is larger than the sum of its proper divisors (1).
22110212100131 is an equidigital number, since it uses as much as digits as its factorization.
22110212100131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 22110212100131 its reverse (13100121201122), we get a palindrome (35210333301253).
The spelling of 22110212100131 in words is "twenty-two trillion, one hundred ten billion, two hundred twelve million, one hundred thousand, one hundred thirty-one".
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