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221114141023 is a prime number
BaseRepresentation
bin1100110111101101101…
…1100000100101011111
3210010201211021011220111
43031323123200211133
512110320210003043
6245324535230451
721655262121316
oct3157333404537
9703654234814
10221114141023
1185857193926
1236a2a818427
1317b0a789149
14a9b834727d
155b41e1b09d
hex337b6e095f

221114141023 has 2 divisors, whose sum is σ = 221114141024. Its totient is φ = 221114141022.

The previous prime is 221114140997. The next prime is 221114141033. The reversal of 221114141023 is 320141411122.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-221114141023 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 221114140985 and 221114141003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (221114141033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110557070511 + 110557070512.

It is an arithmetic number, because the mean of its divisors is an integer number (110557070512).

Almost surely, 2221114141023 is an apocalyptic number.

221114141023 is a deficient number, since it is larger than the sum of its proper divisors (1).

221114141023 is an equidigital number, since it uses as much as digits as its factorization.

221114141023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 221114141023 its reverse (320141411122), we get a palindrome (541255552145).

The spelling of 221114141023 in words is "two hundred twenty-one billion, one hundred fourteen million, one hundred forty-one thousand, twenty-three".