Base | Representation |
---|---|
bin | 1010000011110010000110… |
… | …10000010111101000011111 |
3 | 2220022200010110111222020212 |
4 | 11001321003100113220133 |
5 | 10344404142221021400 |
6 | 115013514551203035 |
7 | 4442063265113231 |
oct | 501710320275037 |
9 | 86280113458225 |
10 | 22120209938975 |
11 | 7059145924225 |
12 | 259306567647b |
13 | c45c083895c5 |
14 | 5668a3ca2251 |
15 | 2855e6488335 |
hex | 141e43417a1f |
22120209938975 has 12 divisors (see below), whose sum is σ = 27893959653720. Its totient is φ = 17396232900000.
The previous prime is 22120209938969. The next prime is 22120209938977. The reversal of 22120209938975 is 57983990202122.
It is not a de Polignac number, because 22120209938975 - 210 = 22120209937951 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (59).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (22120209938977) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 7498374776 + ... + 7498377725.
It is an arithmetic number, because the mean of its divisors is an integer number (2324496637810).
Almost surely, 222120209938975 is an apocalyptic number.
22120209938975 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
22120209938975 is a deficient number, since it is larger than the sum of its proper divisors (5773749714745).
22120209938975 is a wasteful number, since it uses less digits than its factorization.
22120209938975 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14996752570 (or 14996752565 counting only the distinct ones).
The product of its (nonzero) digits is 9797760, while the sum is 59.
The spelling of 22120209938975 in words is "twenty-two trillion, one hundred twenty billion, two hundred nine million, nine hundred thirty-eight thousand, nine hundred seventy-five".
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