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2214033223333 = 5341774211761
BaseRepresentation
bin100000001101111110101…
…010011110111010100101
321211122210210010010212211
4200031332222132322211
5242233320001121313
64413040211443421
7315646543612441
oct40157652367245
97748723103784
102214033223333
11783a6a042418
122b91172b6571
13130a23025599
1479234615821
153c8d3448e3d
hex2037ea9eea5

2214033223333 has 4 divisors (see below), whose sum is σ = 2255807435148. Its totient is φ = 2172259011520.

The previous prime is 2214033223273. The next prime is 2214033223481. The reversal of 2214033223333 is 3333223304122.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1709090811684 + 504942411649 = 1307322^2 + 710593^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2214033223333 is a prime.

It is a super-2 number, since 2×22140332233332 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2214033223295 and 2214033223304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2214033283333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20887105828 + ... + 20887105933.

It is an arithmetic number, because the mean of its divisors is an integer number (563951858787).

Almost surely, 22214033223333 is an apocalyptic number.

It is an amenable number.

2214033223333 is a deficient number, since it is larger than the sum of its proper divisors (41774211815).

2214033223333 is an equidigital number, since it uses as much as digits as its factorization.

2214033223333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41774211814.

The product of its (nonzero) digits is 46656, while the sum is 31.

Adding to 2214033223333 its reverse (3333223304122), we get a palindrome (5547256527455).

It can be divided in two parts, 221403 and 3223333, that added together give a square (3444736 = 18562).

The spelling of 2214033223333 in words is "two trillion, two hundred fourteen billion, thirty-three million, two hundred twenty-three thousand, three hundred thirty-three".

Divisors: 1 53 41774211761 2214033223333