| Base | Representation |
|---|---|
| bin | 100000010100100101110… |
| … | …010100011011010110100 |
| 3 | 21212100010111220111202000 |
| 4 | 200110211302203122310 |
| 5 | 242342334304220200 |
| 6 | 4420212441215300 |
| 7 | 316320503231610 |
| oct | 40244562433264 |
| 9 | 7770114814660 |
| 10 | 2221132101300 |
| 11 | 786a82191512 |
| 12 | 2ba578791530 |
| 13 | 1315b496b3a8 |
| 14 | 79709350340 |
| 15 | 3cb9b795300 |
| hex | 20525ca36b4 |
2221132101300 has 288 divisors, whose sum is σ = 8162440070400. Its totient is φ = 507573112320.
The previous prime is 2221132101289. The next prime is 2221132101311. The reversal of 2221132101300 is 31012311222.
2221132101300 is a `hidden beast` number, since 2 + 2 + 211 + 321 + 0 + 130 + 0 = 666.
It is an interprime number because it is at equal distance from previous prime (2221132101289) and next prime (2221132101311).
It is a super-2 number, since 2×22211321013002 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 106831306 + ... + 106852094.
It is an arithmetic number, because the mean of its divisors is an integer number (28341805800).
Almost surely, 22221132101300 is an apocalyptic number.
2221132101300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 2221132101300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (4081220035200).
2221132101300 is an abundant number, since it is smaller than the sum of its proper divisors (5941307969100).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2221132101300 is a wasteful number, since it uses less digits than its factorization.
2221132101300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26472 (or 26459 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 2221132101300 its reverse (31012311222), we get a palindrome (2252144412522).
The spelling of 2221132101300 in words is "two trillion, two hundred twenty-one billion, one hundred thirty-two million, one hundred one thousand, three hundred".
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