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22212020013 = 37404006671
BaseRepresentation
bin10100101011111100…
…001000011100101101
32010022222211112020220
4110223330020130231
5330442234120023
614112024401553
71414302024561
oct245374103455
963288745226
1022212020013
119469119437
12437a9162b9
13212ca57411
141109db16a1
158a005e3e3
hex52bf0872d

22212020013 has 4 divisors (see below), whose sum is σ = 29616026688. Its totient is φ = 14808013340.

The previous prime is 22212020003. The next prime is 22212020071. The reversal of 22212020013 is 31002021222.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 22212020013 - 24 = 22212019997 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 22212019974 and 22212020001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (22212020003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3702003333 + ... + 3702003338.

It is an arithmetic number, because the mean of its divisors is an integer number (7404006672).

Almost surely, 222212020013 is an apocalyptic number.

It is an amenable number.

22212020013 is a deficient number, since it is larger than the sum of its proper divisors (7404006675).

22212020013 is an equidigital number, since it uses as much as digits as its factorization.

22212020013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7404006674.

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 22212020013 its reverse (31002021222), we get a palindrome (53214041235).

The spelling of 22212020013 in words is "twenty-two billion, two hundred twelve million, twenty thousand, thirteen".

Divisors: 1 3 7404006671 22212020013