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22240410131 is a prime number
BaseRepresentation
bin10100101101101000…
…011011101000010011
32010101222020220011202
4110231220123220103
5331022021111011
614114521101415
71415065236602
oct245550335023
963358226152
1022240410131
11948314a345
12438832786b
1321358b76c4
14110da81a39
158a27bb23b
hex52da1ba13

22240410131 has 2 divisors, whose sum is σ = 22240410132. Its totient is φ = 22240410130.

The previous prime is 22240410103. The next prime is 22240410133. The reversal of 22240410131 is 13101404222.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 22240410131 - 230 = 21166668307 is a prime.

It is a super-2 number, since 2×222404101312 (a number of 21 digits) contains 22 as substring.

Together with 22240410133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (22240410133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11120205065 + 11120205066.

It is an arithmetic number, because the mean of its divisors is an integer number (11120205066).

Almost surely, 222240410131 is an apocalyptic number.

22240410131 is a deficient number, since it is larger than the sum of its proper divisors (1).

22240410131 is an equidigital number, since it uses as much as digits as its factorization.

22240410131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 22240410131 its reverse (13101404222), we get a palindrome (35341814353).

The spelling of 22240410131 in words is "twenty-two billion, two hundred forty million, four hundred ten thousand, one hundred thirty-one".