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222413143500151 is a prime number
BaseRepresentation
bin110010100100100010011000…
…011010010110010101110111
31002011111111012101022202211221
4302210202120122112111313
5213123004104214001101
62105011104303411211
764563551014552102
oct6244423032262567
91064444171282757
10222413143500151
116495a98023078a
1220b411a78b3b07
13971461447b526
143cccbd4335739
151aaa722646aa1
hexca4898696577

222413143500151 has 2 divisors, whose sum is σ = 222413143500152. Its totient is φ = 222413143500150.

The previous prime is 222413143500113. The next prime is 222413143500187. The reversal of 222413143500151 is 151005341314222.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 222413143500151 - 221 = 222413141402999 is a prime.

It is a super-2 number, since 2×2224131435001512 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (222413143500851) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 111206571750075 + 111206571750076.

It is an arithmetic number, because the mean of its divisors is an integer number (111206571750076).

Almost surely, 2222413143500151 is an apocalyptic number.

222413143500151 is a deficient number, since it is larger than the sum of its proper divisors (1).

222413143500151 is an equidigital number, since it uses as much as digits as its factorization.

222413143500151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 222413143500151 its reverse (151005341314222), we get a palindrome (373418484814373).

The spelling of 222413143500151 in words is "two hundred twenty-two trillion, four hundred thirteen billion, one hundred forty-three million, five hundred thousand, one hundred fifty-one".