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2230254115 = 5895011807
BaseRepresentation
bin1000010011101110…
…1111101000100011
312202102121122111021
42010323233220203
514031421112430
61005150030311
7106160563405
oct20473575043
95672548437
102230254115
11a44a13a21
12522aa8397
132970951bb
141722b4b75
15d0be607a
hex84eefa23

2230254115 has 8 divisors (see below), whose sum is σ = 2706376320. Its totient is φ = 1764155712.

The previous prime is 2230254101. The next prime is 2230254121. The reversal of 2230254115 is 5114520322.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2230254115 - 25 = 2230254083 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2230254115.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2505459 + ... + 2506348.

It is an arithmetic number, because the mean of its divisors is an integer number (338297040).

Almost surely, 22230254115 is an apocalyptic number.

2230254115 is a deficient number, since it is larger than the sum of its proper divisors (476122205).

2230254115 is an equidigital number, since it uses as much as digits as its factorization.

2230254115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5011901.

The product of its (nonzero) digits is 2400, while the sum is 25.

The square root of 2230254115 is about 47225.5663279965. The cubic root of 2230254115 is about 1306.5261798915.

Adding to 2230254115 its reverse (5114520322), we get a palindrome (7344774437).

The spelling of 2230254115 in words is "two billion, two hundred thirty million, two hundred fifty-four thousand, one hundred fifteen".

Divisors: 1 5 89 445 5011807 25059035 446050823 2230254115