Base | Representation |
---|---|
bin | 10100110010000010… |
… | …101101000011110111 |
3 | 2010121010111021121111 |
4 | 110302002231003313 |
5 | 331144441444020 |
6 | 14130123055451 |
7 | 1416654215440 |
oct | 246202550367 |
9 | 63533437544 |
10 | 22314406135 |
11 | 951099a66a |
12 | 43a9071587 |
13 | 2148025018 |
14 | 11198242c7 |
15 | 8a9035d5a |
hex | 5320ad0f7 |
22314406135 has 32 divisors (see below), whose sum is σ = 30901852800. Its totient is φ = 15152320512.
The previous prime is 22314406129. The next prime is 22314406139. The reversal of 22314406135 is 53160441322.
It is not a de Polignac number, because 22314406135 - 211 = 22314404087 is a prime.
It is a super-3 number, since 3×223144061353 (a number of 32 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 22314406097 and 22314406106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (22314406139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1751107 + ... + 1763803.
It is an arithmetic number, because the mean of its divisors is an integer number (965682900).
Almost surely, 222314406135 is an apocalyptic number.
22314406135 is a deficient number, since it is larger than the sum of its proper divisors (8587446665).
22314406135 is a wasteful number, since it uses less digits than its factorization.
22314406135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13195.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 22314406135 its reverse (53160441322), we get a palindrome (75474847457).
The spelling of 22314406135 in words is "twenty-two billion, three hundred fourteen million, four hundred six thousand, one hundred thirty-five".
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