Base | Representation |
---|---|
bin | 1010001001101100000100… |
… | …10011100101011010110111 |
3 | 2221001001220101200120102011 |
4 | 11010312002103211122313 |
5 | 10411220233042200044 |
6 | 115251034354225051 |
7 | 4462536000340516 |
oct | 504660223453267 |
9 | 87031811616364 |
10 | 22323131209399 |
11 | 71272066720a9 |
12 | 2606457585187 |
13 | c5c0a6985c57 |
14 | 572633d3467d |
15 | 28aa210ee134 |
hex | 144d824e56b7 |
22323131209399 has 2 divisors, whose sum is σ = 22323131209400. Its totient is φ = 22323131209398.
The previous prime is 22323131209397. The next prime is 22323131209417. The reversal of 22323131209399 is 99390213132322.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 22323131209399 - 21 = 22323131209397 is a prime.
It is a super-3 number, since 3×223231312093993 (a number of 41 digits) contains 333 as substring.
Together with 22323131209397, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (22323131209391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11161565604699 + 11161565604700.
It is an arithmetic number, because the mean of its divisors is an integer number (11161565604700).
Almost surely, 222323131209399 is an apocalyptic number.
22323131209399 is a deficient number, since it is larger than the sum of its proper divisors (1).
22323131209399 is an equidigital number, since it uses as much as digits as its factorization.
22323131209399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 944784, while the sum is 49.
The spelling of 22323131209399 in words is "twenty-two trillion, three hundred twenty-three billion, one hundred thirty-one million, two hundred nine thousand, three hundred ninety-nine".
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