Base | Representation |
---|---|
bin | 1101000000010001100… |
… | …1111101101000100011 |
3 | 210100122222111101210211 |
4 | 3100010121331220203 |
5 | 12130022011324212 |
6 | 250344551034551 |
7 | 22066235326402 |
oct | 3200431755043 |
9 | 710588441724 |
10 | 223412214307 |
11 | 86826409347 |
12 | 3737036ba57 |
13 | 180b5908319 |
14 | ab55633639 |
15 | 5c28a5b9a7 |
hex | 340467da23 |
223412214307 has 2 divisors, whose sum is σ = 223412214308. Its totient is φ = 223412214306.
The previous prime is 223412214301. The next prime is 223412214323. The reversal of 223412214307 is 703412214322.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 223412214307 - 211 = 223412212259 is a prime.
It is a super-3 number, since 3×2234122143073 (a number of 35 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (223412214301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 111706107153 + 111706107154.
It is an arithmetic number, because the mean of its divisors is an integer number (111706107154).
Almost surely, 2223412214307 is an apocalyptic number.
223412214307 is a deficient number, since it is larger than the sum of its proper divisors (1).
223412214307 is an equidigital number, since it uses as much as digits as its factorization.
223412214307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 31.
Adding to 223412214307 its reverse (703412214322), we get a palindrome (926824428629).
The spelling of 223412214307 in words is "two hundred twenty-three billion, four hundred twelve million, two hundred fourteen thousand, three hundred seven".
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