Base | Representation |
---|---|
bin | 1101000010111111101… |
… | …0101001001000001011 |
3 | 210102112212002120210011 |
4 | 3100233322221020023 |
5 | 12133020400420410 |
6 | 250545225132351 |
7 | 22123311163462 |
oct | 3205772511013 |
9 | 712485076704 |
10 | 224142201355 |
11 | 8707047a426 |
12 | 3753492a0b7 |
13 | 181a0c16817 |
14 | abc45759d9 |
15 | 5c6cba418a |
hex | 342fea920b |
224142201355 has 8 divisors (see below), whose sum is σ = 269150805072. Its totient is φ = 179193652128.
The previous prime is 224142201347. The next prime is 224142201377. The reversal of 224142201355 is 553102241422.
It is a happy number.
224142201355 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 224142201355 - 23 = 224142201347 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15005409 + ... + 15020338.
It is an arithmetic number, because the mean of its divisors is an integer number (33643850634).
Almost surely, 2224142201355 is an apocalyptic number.
224142201355 is a deficient number, since it is larger than the sum of its proper divisors (45008603717).
224142201355 is a wasteful number, since it uses less digits than its factorization.
224142201355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30027245.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 224142201355 its reverse (553102241422), we get a palindrome (777244442777).
The spelling of 224142201355 in words is "two hundred twenty-four billion, one hundred forty-two million, two hundred one thousand, three hundred fifty-five".
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