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225034115077 is a prime number
BaseRepresentation
bin1101000110010100010…
…1000001100000000101
3210111212000101111101201
43101211011001200011
512141332213140302
6251213530022501
722154361263152
oct3214505014005
9714760344351
10225034115077
1187488989402
1237743577a31
13182b393b715
14ac6abc9229
155cc1134c87
hex3465141805

225034115077 has 2 divisors, whose sum is σ = 225034115078. Its totient is φ = 225034115076.

The previous prime is 225034115023. The next prime is 225034115081. The reversal of 225034115077 is 770511430522.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 165485426401 + 59548688676 = 406799^2 + 244026^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-225034115077 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (225034115017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 112517057538 + 112517057539.

It is an arithmetic number, because the mean of its divisors is an integer number (112517057539).

Almost surely, 2225034115077 is an apocalyptic number.

It is an amenable number.

225034115077 is a deficient number, since it is larger than the sum of its proper divisors (1).

225034115077 is an equidigital number, since it uses as much as digits as its factorization.

225034115077 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 58800, while the sum is 37.

Adding to 225034115077 its reverse (770511430522), we get a palindrome (995545545599).

The spelling of 225034115077 in words is "two hundred twenty-five billion, thirty-four million, one hundred fifteen thousand, seventy-seven".