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225651440113 = 1120513767283
BaseRepresentation
bin1101001000100111011…
…1111011100111110001
3210120110000222212010221
43102021313323213301
512144113232040423
6251355101253041
722205565410461
oct3221167734761
9716400885127
10225651440113
118777539a890
1237896264181
13183817c1cc8
14acc8ba1ba1
155d0a425e5d
hex3489dfb9f1

225651440113 has 4 divisors (see below), whose sum is σ = 246165207408. Its totient is φ = 205137672820.

The previous prime is 225651440107. The next prime is 225651440123. The reversal of 225651440113 is 311044156522.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 225651440113 - 25 = 225651440081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (225651440123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10256883631 + ... + 10256883652.

It is an arithmetic number, because the mean of its divisors is an integer number (61541301852).

Almost surely, 2225651440113 is an apocalyptic number.

It is an amenable number.

225651440113 is a deficient number, since it is larger than the sum of its proper divisors (20513767295).

225651440113 is a wasteful number, since it uses less digits than its factorization.

225651440113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20513767294.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 225651440113 its reverse (311044156522), we get a palindrome (536695596635).

The spelling of 225651440113 in words is "two hundred twenty-five billion, six hundred fifty-one million, four hundred forty thousand, one hundred thirteen".

Divisors: 1 11 20513767283 225651440113