Base | Representation |
---|---|
bin | 1101011000110110101… |
… | …0111100110001011101 |
3 | 210222200210121101110102 |
4 | 3112031222330301131 |
5 | 12232030042104432 |
6 | 253355402550445 |
7 | 22421602463111 |
oct | 3261552746135 |
9 | 728623541412 |
10 | 230010113117 |
11 | 89601792384 |
12 | 386b1b08425 |
13 | 188c7815465 |
14 | b1bd9dd741 |
15 | 5eb2de9962 |
hex | 358dabcc5d |
230010113117 has 2 divisors, whose sum is σ = 230010113118. Its totient is φ = 230010113116.
The previous prime is 230010113093. The next prime is 230010113141. The reversal of 230010113117 is 711311010032.
It is a balanced prime because it is at equal distance from previous prime (230010113093) and next prime (230010113141).
It can be written as a sum of positive squares in only one way, i.e., 221571669796 + 8438443321 = 470714^2 + 91861^2 .
It is a cyclic number.
It is not a de Polignac number, because 230010113117 - 214 = 230010096733 is a prime.
It is a super-3 number, since 3×2300101131173 (a number of 35 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (230010113197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115005056558 + 115005056559.
It is an arithmetic number, because the mean of its divisors is an integer number (115005056559).
Almost surely, 2230010113117 is an apocalyptic number.
It is an amenable number.
230010113117 is a deficient number, since it is larger than the sum of its proper divisors (1).
230010113117 is an equidigital number, since it uses as much as digits as its factorization.
230010113117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 126, while the sum is 20.
Adding to 230010113117 its reverse (711311010032), we get a palindrome (941321123149).
The spelling of 230010113117 in words is "two hundred thirty billion, ten million, one hundred thirteen thousand, one hundred seventeen".
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