2301211130117 has 2 divisors, whose sum is σ = 2301211130118. Its totient is φ = 2301211130116.

The previous prime is 2301211129991. The next prime is 2301211130123. The reversal of 2301211130117 is 7110311121032.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1818611376481 + 482599753636 = 1348559^2 + 694694^2 .

It is a cyclic number.

It is not a de Polignac number, because 2301211130117 - 2¹⁰ = 2301211129093 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2301211130092 and 2301211130101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2301211130167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1150605565058 + 1150605565059.

It is an arithmetic number, because the mean of its divisors is an integer number (1150605565059).

Almost surely, 2^{2301211130117} is an apocalyptic number.

It is an amenable number.

2301211130117 is a deficient number, since it is larger than the sum of its proper divisors (1).

2301211130117 is an equidigital number, since it uses as much as digits as its factorization.

2301211130117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 23.

Adding to 2301211130117 its reverse (7110311121032), we get a palindrome (9411522251149).

The spelling of 2301211130117 in words is "two trillion, three hundred one billion, two hundred eleven million, one hundred thirty thousand, one hundred seventeen".