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23021100000011 is a prime number
BaseRepresentation
bin1010011110000000001000…
…11111001110001100001011
310000111210111001002211200202
411033000010133032030023
511004134203100000021
6120543425231522415
74564135214226011
oct517000437161413
9100453431084622
1023021100000011
117376214878053
1226b978798940b
13cacb5a36c239
145983275788b1
1529dc71bcba0b
hex14f0047ce30b

23021100000011 has 2 divisors, whose sum is σ = 23021100000012. Its totient is φ = 23021100000010.

The previous prime is 23021099999951. The next prime is 23021100000013. The reversal of 23021100000011 is 11000000112032.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 23021100000011 - 226 = 23021032891147 is a prime.

Together with 23021100000013, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 23021099999938 and 23021100000001.

It is not a weakly prime, because it can be changed into another prime (23021100000013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11510550000005 + 11510550000006.

It is an arithmetic number, because the mean of its divisors is an integer number (11510550000006).

Almost surely, 223021100000011 is an apocalyptic number.

23021100000011 is a deficient number, since it is larger than the sum of its proper divisors (1).

23021100000011 is an equidigital number, since it uses as much as digits as its factorization.

23021100000011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 23021100000011 its reverse (11000000112032), we get a palindrome (34021100112043).

The spelling of 23021100000011 in words is "twenty-three trillion, twenty-one billion, one hundred million, eleven", and thus it is an aban number.