Search a number
-
+
23031312149 is a prime number
BaseRepresentation
bin10101011100110001…
…011110111100010101
32012110002110212210002
4111130301132330111
5334132003442044
614325212541045
71443510631436
oct253461367425
965402425702
1023031312149
11984963677a
124569181785
132230703471
141186b1d48d
158ebe4774e
hex55cc5ef15

23031312149 has 2 divisors, whose sum is σ = 23031312150. Its totient is φ = 23031312148.

The previous prime is 23031312107. The next prime is 23031312151. The reversal of 23031312149 is 94121313032.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19374691249 + 3656620900 = 139193^2 + 60470^2 .

It is a cyclic number.

It is not a de Polignac number, because 23031312149 - 220 = 23030263573 is a prime.

It is a super-3 number, since 3×230313121493 (a number of 32 digits) contains 333 as substring.

Together with 23031312151, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23031312169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11515656074 + 11515656075.

It is an arithmetic number, because the mean of its divisors is an integer number (11515656075).

Almost surely, 223031312149 is an apocalyptic number.

It is an amenable number.

23031312149 is a deficient number, since it is larger than the sum of its proper divisors (1).

23031312149 is an equidigital number, since it uses as much as digits as its factorization.

23031312149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 29.

The spelling of 23031312149 in words is "twenty-three billion, thirty-one million, three hundred twelve thousand, one hundred forty-nine".