23101011000133 has 4 divisors (see below), whose sum is σ = 25201102909248. Its totient is φ = 21000919091020.

The previous prime is 23101011000131. The next prime is 23101011000139. The reversal of 23101011000133 is 33100011010132.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 23101011000133 - 2¹ = 23101011000131 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (23101011000131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1050045954541 + ... + 1050045954562.

It is an arithmetic number, because the mean of its divisors is an integer number (6300275727312).

Almost surely, 2^{23101011000133} is an apocalyptic number.

It is an amenable number.

23101011000133 is a deficient number, since it is larger than the sum of its proper divisors (2100091909115).

23101011000133 is a wasteful number, since it uses less digits than its factorization.

23101011000133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2100091909114.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 23101011000133 its reverse (33100011010132), we get a palindrome (56201022010265).

Subtracting 23101011000133 from its reverse (33100011010132), we obtain a palindrome (9999000009999).

The spelling of 23101011000133 in words is "twenty-three trillion, one hundred one billion, eleven million, one hundred thirty-three", and thus it is an aban number.