Base | Representation |
---|---|
bin | 10101100000111011… |
… | …110100010100010011 |
3 | 2012121221211222212112 |
4 | 111200323310110103 |
5 | 334302342130003 |
6 | 14340145215535 |
7 | 1445316236150 |
oct | 254073642423 |
9 | 65557758775 |
10 | 23101130003 |
11 | 9884a92986 |
12 | 45886315ab |
13 | 224200a0c3 |
14 | 11920d5227 |
15 | 9031393d8 |
hex | 560ef4513 |
23101130003 has 8 divisors (see below), whose sum is σ = 26467133280. Its totient is φ = 19751587200.
The previous prime is 23101129969. The next prime is 23101130021. The reversal of 23101130003 is 30003110132.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 23101130003 - 28 = 23101129747 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 23101130003.
It is not an unprimeable number, because it can be changed into a prime (23101130023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4112108 + ... + 4117721.
It is an arithmetic number, because the mean of its divisors is an integer number (3308391660).
Almost surely, 223101130003 is an apocalyptic number.
23101130003 is a deficient number, since it is larger than the sum of its proper divisors (3366003277).
23101130003 is an equidigital number, since it uses as much as digits as its factorization.
23101130003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8230237.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 23101130003 its reverse (30003110132), we get a palindrome (53104240135).
The spelling of 23101130003 in words is "twenty-three billion, one hundred one million, one hundred thirty thousand, three".
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