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23101130003 = 74018229829
BaseRepresentation
bin10101100000111011…
…110100010100010011
32012121221211222212112
4111200323310110103
5334302342130003
614340145215535
71445316236150
oct254073642423
965557758775
1023101130003
119884a92986
1245886315ab
13224200a0c3
1411920d5227
159031393d8
hex560ef4513

23101130003 has 8 divisors (see below), whose sum is σ = 26467133280. Its totient is φ = 19751587200.

The previous prime is 23101129969. The next prime is 23101130021. The reversal of 23101130003 is 30003110132.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 23101130003 - 28 = 23101129747 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 23101130003.

It is not an unprimeable number, because it can be changed into a prime (23101130023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4112108 + ... + 4117721.

It is an arithmetic number, because the mean of its divisors is an integer number (3308391660).

Almost surely, 223101130003 is an apocalyptic number.

23101130003 is a deficient number, since it is larger than the sum of its proper divisors (3366003277).

23101130003 is an equidigital number, since it uses as much as digits as its factorization.

23101130003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8230237.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 23101130003 its reverse (30003110132), we get a palindrome (53104240135).

The spelling of 23101130003 in words is "twenty-three billion, one hundred one million, one hundred thirty thousand, three".

Divisors: 1 7 401 2807 8229829 57608803 3300161429 23101130003