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231012140035 = 5104774409891
BaseRepresentation
bin1101011100100101100…
…1011000010000000011
3211002021122002121222111
43113021121120100003
512241103101440120
6254043035520151
722455460535305
oct3271131302003
9732248077874
10231012140035
1189a7636aaa6
12389315b9057
1318a272b20b1
14b276b17975
156020d7b75a
hex35c9658403

231012140035 has 8 divisors (see below), whose sum is σ = 277241090256. Its totient is φ = 184792030560.

The previous prime is 231012139961. The next prime is 231012140057. The reversal of 231012140035 is 530041210132.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 231012140035 - 27 = 231012139907 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 231012139988 and 231012140015.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2152561 + ... + 2257330.

It is an arithmetic number, because the mean of its divisors is an integer number (34655136282).

Almost surely, 2231012140035 is an apocalyptic number.

231012140035 is a deficient number, since it is larger than the sum of its proper divisors (46228950221).

231012140035 is a wasteful number, since it uses less digits than its factorization.

231012140035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4420373.

The product of its (nonzero) digits is 720, while the sum is 22.

Adding to 231012140035 its reverse (530041210132), we get a palindrome (761053350167).

The spelling of 231012140035 in words is "two hundred thirty-one billion, twelve million, one hundred forty thousand, thirty-five".

Divisors: 1 5 10477 52385 4409891 22049455 46202428007 231012140035