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231044113 = 1063217351
BaseRepresentation
bin11011100010101…
…11010000010001
3121002202020221101
431301113100101
5433121402423
634532024401
75503561666
oct1561272021
9532666841
10231044113
11109466953
1265462101
1338b365c1
1422983a6d
151543c7ad
hexdc57411

231044113 has 4 divisors (see below), whose sum is σ = 231262528. Its totient is φ = 230825700.

The previous prime is 231044087. The next prime is 231044159. The reversal of 231044113 is 311440132.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 231044113 - 221 = 228946961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (231044813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107613 + ... + 109738.

It is an arithmetic number, because the mean of its divisors is an integer number (57815632).

Almost surely, 2231044113 is an apocalyptic number.

It is an amenable number.

231044113 is a deficient number, since it is larger than the sum of its proper divisors (218415).

231044113 is a wasteful number, since it uses less digits than its factorization.

231044113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 218414.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 231044113 is about 15200.1352954505. The cubic root of 231044113 is about 613.6182989423.

Adding to 231044113 its reverse (311440132), we get a palindrome (542484245).

The spelling of 231044113 in words is "two hundred thirty-one million, forty-four thousand, one hundred thirteen".

Divisors: 1 1063 217351 231044113