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231044440141 is a prime number
BaseRepresentation
bin1101011100101101010…
…0100110000001001101
3211002100212212122101201
43113023110212001031
512241134334041031
6254050152105501
722456332223564
oct3271324460115
9732325778351
10231044440141
1189a926215a9
1238940395291
1318a30bb0c98
14b27b124bdb
156023b0bd61
hex35cb52604d

231044440141 has 2 divisors, whose sum is σ = 231044440142. Its totient is φ = 231044440140.

The previous prime is 231044440117. The next prime is 231044440147. The reversal of 231044440141 is 141044440132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 175180754116 + 55863686025 = 418546^2 + 236355^2 .

It is a cyclic number.

It is not a de Polignac number, because 231044440141 - 231 = 228896956493 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (231044440147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115522220070 + 115522220071.

It is an arithmetic number, because the mean of its divisors is an integer number (115522220071).

Almost surely, 2231044440141 is an apocalyptic number.

It is an amenable number.

231044440141 is a deficient number, since it is larger than the sum of its proper divisors (1).

231044440141 is an equidigital number, since it uses as much as digits as its factorization.

231044440141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6144, while the sum is 28.

Adding to 231044440141 its reverse (141044440132), we get a palindrome (372088880273).

Subtracting from 231044440141 its reverse (141044440132), we obtain a palindrome (90000000009).

The spelling of 231044440141 in words is "two hundred thirty-one billion, forty-four million, four hundred forty thousand, one hundred forty-one".