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231044440117 is a prime number
BaseRepresentation
bin1101011100101101010…
…0100110000000110101
3211002100212212122100211
43113023110212000311
512241134334040432
6254050152105421
722456332223531
oct3271324460065
9732325778324
10231044440117
1189a92621587
1238940395271
1318a30bb0c7a
14b27b124bc1
156023b0bd47
hex35cb526035

231044440117 has 2 divisors, whose sum is σ = 231044440118. Its totient is φ = 231044440116.

The previous prime is 231044440069. The next prime is 231044440141. The reversal of 231044440117 is 711044440132.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 166361199876 + 64683240241 = 407874^2 + 254329^2 .

It is a cyclic number.

It is not a de Polignac number, because 231044440117 - 211 = 231044438069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (231044440147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115522220058 + 115522220059.

It is an arithmetic number, because the mean of its divisors is an integer number (115522220059).

Almost surely, 2231044440117 is an apocalyptic number.

It is an amenable number.

231044440117 is a deficient number, since it is larger than the sum of its proper divisors (1).

231044440117 is an equidigital number, since it uses as much as digits as its factorization.

231044440117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10752, while the sum is 31.

Adding to 231044440117 its reverse (711044440132), we get a palindrome (942088880249).

The spelling of 231044440117 in words is "two hundred thirty-one billion, forty-four million, four hundred forty thousand, one hundred seventeen".