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231100013 is a prime number
BaseRepresentation
bin11011100011001…
…00111001101101
3121002212002121202
431301210321231
5433130200023
634533135245
75504213654
oct1561447155
9532762552
10231100013
111094a4951
126548a525
1338b55b91
142299a19b
151544e128
hexdc64e6d

231100013 has 2 divisors, whose sum is σ = 231100014. Its totient is φ = 231100012.

The previous prime is 231100003. The next prime is 231100027. The reversal of 231100013 is 310001132.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 150136009 + 80964004 = 12253^2 + 8998^2 .

It is a cyclic number.

It is not a de Polignac number, because 231100013 - 24 = 231099997 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 231099967 and 231100003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (231100003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115550006 + 115550007.

It is an arithmetic number, because the mean of its divisors is an integer number (115550007).

Almost surely, 2231100013 is an apocalyptic number.

It is an amenable number.

231100013 is a deficient number, since it is larger than the sum of its proper divisors (1).

231100013 is an equidigital number, since it uses as much as digits as its factorization.

231100013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 11.

The square root of 231100013 is about 15201.9739836641. The cubic root of 231100013 is about 613.6677822733.

Adding to 231100013 its reverse (310001132), we get a palindrome (541101145).

It can be divided in two parts, 231 and 100013, that multiplied together give a triangular number (23103003 = T6797).

The spelling of 231100013 in words is "two hundred thirty-one million, one hundred thousand, thirteen".