Base | Representation |
---|---|
bin | 100001101000010010100… |
… | …001010010100101100101 |
3 | 22011221002210002101120000 |
4 | 201220102201102211211 |
5 | 300330413244401041 |
6 | 4525354333131513 |
7 | 325651545265356 |
oct | 41502241224545 |
9 | 8157083071500 |
10 | 2311003122021 |
11 | 811100018560 |
12 | 313a7a329b99 |
13 | 139c07b41669 |
14 | 7dbd3075d2d |
15 | 401ab645bb6 |
hex | 21a12852965 |
2311003122021 has 40 divisors (see below), whose sum is σ = 3769858022304. Its totient is φ = 1399202592480.
The previous prime is 2311003122013. The next prime is 2311003122059. The reversal of 2311003122021 is 1202213001132.
2311003122021 is a `hidden beast` number, since 2 + 311 + 0 + 0 + 312 + 20 + 21 = 666.
It is not a de Polignac number, because 2311003122021 - 23 = 2311003122013 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 2311003121985 and 2311003122003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2311003122061) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 412435 + ... + 2189088.
Almost surely, 22311003122021 is an apocalyptic number.
It is an amenable number.
2311003122021 is a deficient number, since it is larger than the sum of its proper divisors (1458854900283).
2311003122021 is a wasteful number, since it uses less digits than its factorization.
2311003122021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2602543 (or 2602534 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 2311003122021 its reverse (1202213001132), we get a palindrome (3513216123153).
The spelling of 2311003122021 in words is "two trillion, three hundred eleven billion, three million, one hundred twenty-two thousand, twenty-one".
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