2311131322013 has 4 divisors (see below), whose sum is σ = 2311175680128. Its totient is φ = 2311086963900.

The previous prime is 2311131322009. The next prime is 2311131322069. The reversal of 2311131322013 is 3102231311132.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2311131322013 - 2² = 2311131322009 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2311131322013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2311131321013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22100813 + ... + 22205138.

It is an arithmetic number, because the mean of its divisors is an integer number (577793920032).

Almost surely, 2^{2311131322013} is an apocalyptic number.

It is an amenable number.

2311131322013 is a deficient number, since it is larger than the sum of its proper divisors (44358115).

2311131322013 is an equidigital number, since it uses as much as digits as its factorization.

2311131322013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44358114.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 2311131322013 its reverse (3102231311132), we get a palindrome (5413362633145).

The spelling of 2311131322013 in words is "two trillion, three hundred eleven billion, one hundred thirty-one million, three hundred twenty-two thousand, thirteen".