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231113301 = 377037767
BaseRepresentation
bin11011100011010…
…00001001010101
3121002212202211220
431301220021111
5433131111201
634533320553
75504300466
oct1561501125
9532782756
10231113301
11109503931
1265496159
1338b5bc43
14229a0d6d
1515453036
hexdc68255

231113301 has 4 divisors (see below), whose sum is σ = 308151072. Its totient is φ = 154075532.

The previous prime is 231113293. The next prime is 231113303. The reversal of 231113301 is 103311132.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 231113301 - 23 = 231113293 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (231113303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38518881 + ... + 38518886.

It is an arithmetic number, because the mean of its divisors is an integer number (77037768).

Almost surely, 2231113301 is an apocalyptic number.

It is an amenable number.

231113301 is a deficient number, since it is larger than the sum of its proper divisors (77037771).

231113301 is an equidigital number, since it uses as much as digits as its factorization.

231113301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 77037770.

The product of its (nonzero) digits is 54, while the sum is 15.

The square root of 231113301 is about 15202.4110258867. The cubic root of 231113301 is about 613.6795437917.

Adding to 231113301 its reverse (103311132), we get a palindrome (334424433).

The spelling of 231113301 in words is "two hundred thirty-one million, one hundred thirteen thousand, three hundred one".

Divisors: 1 3 77037767 231113301