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23112112312141 is a prime number
BaseRepresentation
bin1010100000101001101010…
…01111101000111101001101
310000211111101211211022222221
411100110311033220331031
511012132101222442031
6121053320253335341
74603536455142616
oct520246517507515
9100744354738887
1023112112312141
117400878961236
122713347797551
13cb8602b1c778
1459c8bcaaac0d
152a12ebd6ca11
hex1505353e8f4d

23112112312141 has 2 divisors, whose sum is σ = 23112112312142. Its totient is φ = 23112112312140.

The previous prime is 23112112312109. The next prime is 23112112312151. The reversal of 23112112312141 is 14121321121132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 23088073050025 + 24039262116 = 4805005^2 + 155046^2 .

It is a cyclic number.

It is not a de Polignac number, because 23112112312141 - 25 = 23112112312109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23112112312151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11556056156070 + 11556056156071.

It is an arithmetic number, because the mean of its divisors is an integer number (11556056156071).

Almost surely, 223112112312141 is an apocalyptic number.

It is an amenable number.

23112112312141 is a deficient number, since it is larger than the sum of its proper divisors (1).

23112112312141 is an equidigital number, since it uses as much as digits as its factorization.

23112112312141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 576, while the sum is 25.

Adding to 23112112312141 its reverse (14121321121132), we get a palindrome (37233433433273).

The spelling of 23112112312141 in words is "twenty-three trillion, one hundred twelve billion, one hundred twelve million, three hundred twelve thousand, one hundred forty-one".