Base | Representation |
---|---|
bin | 1010100000101111110110… |
… | …01011110101011000110111 |
3 | 10000211210222021200002012010 |
4 | 11100113323023311120313 |
5 | 11012210401400001010 |
6 | 121055030003455303 |
7 | 4604014661225121 |
oct | 520277313653067 |
9 | 100753867602163 |
10 | 23115433203255 |
11 | 7402222474948 |
12 | 2713b13987533 |
13 | cb8a11b379b3 |
14 | 59cb15b64211 |
15 | 2a144369a620 |
hex | 1505fb2f5637 |
23115433203255 has 64 divisors (see below), whose sum is σ = 38275761438720. Its totient is φ = 11907108210816.
The previous prime is 23115433203133. The next prime is 23115433203281. The reversal of 23115433203255 is 55230233451132.
It is not a de Polignac number, because 23115433203255 - 222 = 23115429008951 is a prime.
It is a super-3 number, since 3×231154332032553 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 10578324 + ... + 12575046.
It is an arithmetic number, because the mean of its divisors is an integer number (598058772480).
Almost surely, 223115433203255 is an apocalyptic number.
23115433203255 is a deficient number, since it is larger than the sum of its proper divisors (15160328235465).
23115433203255 is a wasteful number, since it uses less digits than its factorization.
23115433203255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1997020.
The product of its (nonzero) digits is 324000, while the sum is 39.
Adding to 23115433203255 its reverse (55230233451132), we get a palindrome (78345666654387).
The spelling of 23115433203255 in words is "twenty-three trillion, one hundred fifteen billion, four hundred thirty-three million, two hundred three thousand, two hundred fifty-five".
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