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23116433 = 471732843
BaseRepresentation
bin101100000101…
…1101010010001
31121111102210012
41120023222101
521404211213
62143244305
7400325564
oct130135221
947442705
1023116433
111205979a
1278a9695
134a34a82
1430da4db
1520694a8
hex160ba91

23116433 has 8 divisors (see below), whose sum is σ = 23753088. Its totient is φ = 22485904.

The previous prime is 23116417. The next prime is 23116441. The reversal of 23116433 is 33461132.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 23116433 - 24 = 23116417 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 23116399 and 23116408.

It is not an unprimeable number, because it can be changed into a prime (23116463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6710 + ... + 9552.

It is an arithmetic number, because the mean of its divisors is an integer number (2969136).

Almost surely, 223116433 is an apocalyptic number.

It is an amenable number.

23116433 is a deficient number, since it is larger than the sum of its proper divisors (636655).

23116433 is a wasteful number, since it uses less digits than its factorization.

23116433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3063.

The product of its digits is 1296, while the sum is 23.

The square root of 23116433 is about 4807.9551786596. The cubic root of 23116433 is about 284.8657744878.

Adding to 23116433 its reverse (33461132), we get a palindrome (56577565).

The spelling of 23116433 in words is "twenty-three million, one hundred sixteen thousand, four hundred thirty-three".

Divisors: 1 47 173 2843 8131 133621 491839 23116433